Gas Krypton

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FAQ about Gas Krypton

Is $11,000 a fair price for installing 16 triple pane krypton gas samsonite windows.? well let me say this i have been in the field 20yrs
and this is not bad or good
if all they had to do was drop them in then its a bit high.
But im sure thats not the case if they are removin the old windows install the new and outside tirm ect then its a fair price. its hard to say cuz you did not give more info.
So if they have to do work on the caseing outside and other things its Ok like I said If there just gonna put the windows in and use what you have there then I would say give me a better offer
Goodluck

what is the ratio of the average velocity of krypton gas atoms to that of nitrogen molecules at the same...? what is the ratio of the average velocity of krypton gas atoms to that of nitrogen molecules at the same temperature and pressure? show work and explain if possible. THANKS so much :)

I need help with a chemistry problem regarding average kinetic energy of krypton and argon gas molecules.? The question is: Two gas cylinders are identical. One contains the monatomic gas argon (Ar) and the other contains an equal mass of the monatomic gas krypton (Kr). The pressures in the cylinders are the same, but the temperatures are different. Determine the ratio of the average kinetic energy of a krypton atom to the average kinetic energy of an argon atom. An explanation would also be fantastic. Thanks a ton. speed of motion has a lot to do with temperature
u = speed = [3RT/M]^1/2
R = 8.314 kg-m^2/s^2-mol-K
K is temperature in kelvin, you don't give the temperatures. so, let's assume that both are at room temperature for now
M is molar mass
for Ar, u = [3 x 8.314 x 273/ 40]^1/2 = 13 m/s
for Kr, u = [3 x 8.314 x 273 / 83.8]^1/2 = 9 m/s
the heavier gas will move slower. the ratio of Kr:Ar would be 9:13 or 0.69:1
you would need the temperatures of both gases, plug those values in to the equation, determine the new ratio

sample of krypton gas collected at STP occupies a volume of 30.3 L. How many moles of gas does the sample cont? 1. sample of krypton gas collected at STP occupies a volume of 30.3 L. How many moles of gas does the sample contain? 2. A sample of methane gas that occupies a volume of 35.2 L at a temperature of 0 oC and a pressure of 1 atm contains moles of gas 3. A sample of xenon gas that occupies a volume of 40.4 L at a temperature of 0 oC and a pressure of 1 atm contains moles of gas All three of your examples have the gas at STP, which is 1 atmosphere pressure and
0°C. All gases have a molar volume of 22.414 liters at STP.
So in example 1, if you have 30.3 liters, it's 30.3 / 22.414 = 1.352 moles of Kr
In example 2, you have 35.2 liters, so you have 35.2 / 22.414 = 1.57 moles of methane
and in example 3, you have 40.4 liters, or 40.4 / 22.414 = 1.802 moles.
(The symbol for degrees is a raised circle like this: °)
Hope this answers your question.

What is the mass of a 90.3 mL sample of krypton gas at 1.8oC and 76.98 kPa? What is the mass of a 90.3 mL sample of krypton gas at 1.8oC and 76.98 kPa? -Porfavor? IDEAL GAS LAW
You can use the formula: PV=nRT
P stands for pressure
V for volume
n stands for mole
R is the universal gas constant (Liter X atmosphere / mol X Kelvin)
T is temperature
Manipulate the formula to get n.
n=PV/RT
then,
find the molecular weight of krypton in the periodic table.
Use the formula: molecular weight= mass/n to get the final answer.
Hope this helps. :] Good Luck.

Calculate the number of moles of Krypton gas contained in a 5.00 liter ? Calculate the number of moles of Krypton gas contained in a 5.00 liter container at 6.00 atm 25.0 C(degrees Celsius). If the gas in Argon instead of Krypton; will the answer be the same? Why or why not? Thanks for helping me everyone. p*V = n*R*T, so n = p*V/ (R*T)
T - temperature, K (298 k in your case)
p = 6*101325 Pa
R the universal gas constant (8 point something, look it up somewhere please)
V = 0.005 cubic meters
The answer will be the same because all the numbers in the above equations remain the same, right?

A sample of 30.0 ml of krypton gas, Kr, is at 756 mm Hg and 25.0 degree celsius. What is the new volume if the? A sample of 30.0 ml of krypton gas, Kr, is at 756 mm Hg and 25.0 degree celsius. What is the new volume if the pressure is decreased to 325 mm Hg and the temperature is decreased to -12.5 degree celsius? Hello
use
v1*p1/T1 = v2*p2/T2
and temperature as °K
30*756/298 = v2*325/260,5
v2 = 30*756*260,5/(298*325) = 61 ml
Regards

where can I find a triple pane window with krypton gas, and low E? try home depot or another of the home improvement stores.

How can Krypton be a noble/inert gas if it reacts with fluorine? I'm doing a project of Krypton for chemistry and looking up it's chemical properties. In 1962 it was found to react with fluorine, yet it's a noble gas. Doesn't that mean it's not supposed to react with anything? NO! Noble gasses are difficult to react but not impossible. All of the noble gasses have been combined in the laboratory with Fluorine because it is the most reactive element known. Most of these compounds are explosive, which means they are very tenuously held together and eager to disassociate back to their elemental forms.

A mixture of krypton and hydrogen gas is compressed from a volume of 44.0L to a volume of 40.0L? A mixture of krypton and hydrogen gas is compressed from a volume of 44.0L to a volume of 40.0L, while the pressure is held constant at 58.0atm. Calculate the work done on the gas mixture. Be sure your answer has the correct sign (positive or negative) and the correct number of significant digits. The answer is in kJ. w = -P x (change in V)
w = - 58.0 atm x (-4.0 L) x (101.3 J / 1 L atm) = 24,000 J = 24 kJ (2 sig figs)
The sign is + meaning that work is done on the system. The system is gaining energy equal to the work done on it.

Gas Krypton is from category: Flashlights.