Automobile Thermometer

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Which Property Of Metal? 1. alumimum foil 2. electrical wire 3. pots and pans used for cooking 4. automobile trim 5. mercury thermometer Each of the these objects can be made because of a special property of metal. Which property makes it possible to make each of the objects listed there? ductility, malleability,shininess, and hardness.
If they are in the right order who cares

desperate for help? Out of these inventions, what do you think would be the order of the 10 greatest inventions (in order of importance)? Explain why you chose each one. The inventions are: Computer Automobile Birthday Cake Microwave Motion Picture Alphabet Gunpowder Chocolate Wheel Thermometer Baseball Watches Plastic Brick Lipstick Printing Press Gel Pens Oven Airplane Clock Map Paper Pencil Telephone Refrigerator Compass Money Space Shuttle 1. Paper=to design, spread, and encourage ideas i.e. wheel, political revolution, history.
2. Pencil=to record the stuff
3. Next step is to find the thing most that gets society's economy going=Brick=gotta live somewhere, build centers, and productive tools, i.e. Aqueducts.
4. Gunpowder=Nothing spurs a society more than a successful war
5. Wheel=to grind the gunpowder, to grind grain for bread, and the other obvious stuff.
6. Money=That is definitely needed, once you have currency swishing through society you have goals, and education, and a means of taking advantage of resources
7. Plastic=Gotta have that. Its everywhere!
8. Telephone=A great way to conversed, and in the conversation deals can be made in a flash, pass info, and just plain be happy.
9. Oven=We wouldn't be a very productive society if we all had stomach cramps! A healthy society, a healthy mind.
10. Compass=Part of a healthy mind is knowledge of how to use a compass, know where you are at, and know how to get where you want to get to.

Please help on these two problems? 18) A 1.42 g. sample of a pure compound, with formula M2SO4, was dissolved in water and treated with and excess of aqueous barium chloride, resulting in the precipitation of all the sulfate ions as barium sulfate. The precipitate was collected, dried, and found to weigh 2.33-g. Determine the atomic mass of M, and identify M. 19) Ethylene glycol is the main component in automobile antifreeze. To monitor the temperature of an auto cooling system you intend to use as a meter reads from 0 to 100. You devise a new temperature scale based on the approximate melting and boiling points of typical antifreeze solution (-45 C and 115 C). You wish these points to correspond to 0 A and 100 A (degrees) respectively. a) Derive and expression for converting between A (degree) and C(degree) b) Derive an expression for converting between F (degree) and A (degree) c) At what temperature would your thermometer and a Celsius thermometer give the numerical reading? d) Your thermometer reads 86 A(degrees) Whats the temperature in Celsius and Fahrenheit? e) What is the temperature of 45 C in A (degrees)? Thank you . Can you explain in steps how you do # 18 because I'm having problems with these types of problems:( So you have formula M2 SO4. So4 has a valance of -2 accepts 2 electrons. M must have the valance 1. Chemical formula:
M2 SO4 + 2(Ba Cl)->Ba2 SO4 (precipitate)+ 2 M Cl
From this you find the molar number of the SO4 group. It should be the same as M2 in the M2SO4 formula. So we have the following equations:
1.42=x (Atomic mas of M2SO4)
2.33=x (Atomic mas of Ba2 SO4)
from this you find the Atomic Mas of M2. By applying the formula :
Atomic mass of M2 SO4 =2 Atomic mass of M+ Atomic mas of S+4 Atomic mass of O
The atomic masses you get from tables, fave fun with numeric values.
19) In rescaling there is a formula of of type F(x)=y
If you use Linear formula for F(x) this can fave only the form F(x)=a x +b. If you constrain that at some point the scale will have some given value you can write
F(x1)=a x1+b=y1
F(x2)=a x2+b=y2 from this you will find the constant a and b as equal:
a=(y1-y2)/(x1-x2), b=(y1x2-y2x1)/(x2-x1)
Note: interpolating the function with other Type of function as the scale was not require to be Linear will get you different solution, this can have one, or n degree of freedom. Have fun in doing the numeric and do not forgeth The function for F to celsius is
Function(F degree)=5/9 (F-32)

Actually explain this? I don't just want an answer, I need to know how to do this, please . . Ethylene glycol is the main component in automobile anti-freeze. To monitor the temp, of an auto cooling system, you intend to use a meter that reads from 0 to 100. You devise a new temperature scale based on the approximate melting and boiling points of a typical antifreeze solution(-45 degrees C and 115 degrees C)You wish these points to correspond to O degrees A and 100 degrees A respectively. a)derive an expression for converting between degrees A and degrees C. b)Derive an expression for converting between degrees F and degrees A. c)At what temp. would our thermometer and a Celsius thermometer give the same numerical reading? d)Your thermometer reads 86 degrees A. What is the temp i degrees C and degrees F. e)What is the temp. of 45 degrees C in degrees A. Please help, my book has no info on creating your own temperature system, it only tells how to convert from F to C and vice-versa. . . A.) You can set up a graph to find the slope and intercept. Use chart paper or Excel. When you plot the data that is given (0A = -45C; 100A = 115C) you get a line. If using Excel, add a trendline and show the equation.
The equation of this line is:
y=0.625x + 28.125 which is:
A = 0.625 * C + 28.125
This is how the conversion between F and C was derived.
B.) the same way
C.) Use algebra. Set your equation equal to C such that:
C = 0.625 * C + 28.125 and you will find the intersection of the two scales.
solving for C gives 75 degrees is the temperature you want.
D.) plug into your equation:
A = 0.625 * C + 28.125
86=0.625 * C +28.125 and solve
C = 92.6 degrees A
you should be able to do the same for A to F using the equation you developed and solving algebraically.
E.) plug into your equation again the same way:
A = 0.625 * C + 28.125
A = 0.625 * 45 + 28.125 = use calculator
Now you should be able to find what I did not give to you. (I should not do it all for you). Good luck.

This is really confusing. CHEMISTRY HELP? Ethylene glycol is the main component in automobile antifreeze. To monitor the temperature of an auto cooling system, you intend to use a meter that reads from 0 to 100. You devise a new temperature scale based on the approximate melting and boiling points of a typical antifreeze solution (-45°C and 115°C). You wish these points to correspond to 0° and 100°A, respectively. (a) Derive an expression for converting between °A and °C. (Use T_A for TA.) TC = (b) Derive an expression for converting between °F and °A. TF = (d) Your thermometer reads 65°A. What is the temperature in °C and in °F? (e) What is a temperature of 59°C in °A? the temperature scales are arbitrary. that is the maker gets to choose what is zero (or the lowest) and the highest available. these temp have to be based on some physical event, like freezing or boiling
then the number of divisions is chosen and the scale is extended above and below
there is one scale that is absolute which is the relation of an (ideal) gas according to the rule
Pressure x Volume = K T. by graphing in that case there is an absolute Zero T at which there is ) pressure and 0 Vol, no energy of the gas particles. that is a Physics study
the chemists used the arbitrary systems . to do conversion you would chart and graph the temp in each system. the physical condition, (example melting wax) would be the same in both systems so each would have a number value say 20 deg A and 30 Deg B. One point is not enough, so pick a different event (like the boiling of lead, a high value) then maybe 200 A = 500 Deg B
Now you know that 200A - 20 A = 500 B - 30 B and you can get the ratio of the size of 1 Deg A to B
that give the slope of the line the equation y Deg A = some equation of Deg B
then pick the event where the Y Deg A = Z Deg B the common point for both in this case melting wax 20 A = 30 B and figure the values in the equation y deg A = m x Deg B + b deg B
the Linear straight line equation
Example 32 Deg F = 0 deg C and 212 F = 100 C
so 212-32 F = 100 -0 C or 180 F = 100 C
so divide by 20: 9 F = 5 C or F = 5/9 C and C = 9/5 F
but 0 C = 32 F so
0 C = 5/9 (F - 32) { to make the (..) = 0: and also 32 F = 9/5 x ( 0 C) + 32 F
Notice in one case the (...) is (F- 32) but the other is (..) + 32 that is the confusing part
Mathematically the assumption is y = mx + b, but the m and the b are unknowns not given.
instead we have TWO equations each with a pair of known (y1, x1) low point; and (y2 , x2) high point
use the methods of solving simultaneous equations to find the unknown m and b

chemical foundations = chemistry? ethylene glycol is the main component in automobile antifreeze. To monitor the temperature o an auto cooling system you intend to use a meter that reads from 0 to 100. You devise a new temperature scale based on the approximate melting and boiling points of a typical antifreeze solution ( -45 C and 115 C). You wish these points correspond to 0 Degrees A and 100 Degrees A respectively. a) derive an expression for converting A and C b) Derive an expression for converting between F and A. c) at what temperature would your thermometer and a Celsius thermometer give the same numerical reading? d) Your thermometer reads 86 Degrees A. What is the temperature in C Degrees and F Degrees? e) What is a temperature of 45 Degrees C in A Degrees? *** a ***
you have two points (A, C) = (0, -45), (100, 115)
let's assume the relationship is linear...y = mx+b
m = (y2-y1) / (x2-x1) = (115- -45) / (100 - 0) = 160 / 100 = 1.6
y = 1.5x+b
plug in either point and solve for b
-45 = 1.6x(0) + b
b = -45
so C = 1.6xA - 45
*** b ***
since C = (F - 32) x 5/9
(F-32) x 5/9 = 8/5xA - 45
F-32 = (9/5)x(8/5)xA - (9/5)x(9x5)
F-32 = 72/25 A - 81
F = 2.88 A - 49
*** c ***
when C = A they're equal so substitute A for C and solve...
A = 1.6xA - 45
45 = 0.6A
A = 75 = C
*** d ***
C = 1.6x(86) - 45 = 182.6
*** e ***
C = 1.6A - 45
C+45 = 1.6A
(C+45)/1.6 = A
A = (45+45)/1.6 = 56.24

who wants to help me with physics thermo problems? yeah so basically i have no idea how to do these problems because my teacher hasn't taught our class anything. if you like thermo problems you should help me! (and if you respond with 'do your own homework' or w.e., idgaf i'm lazy and confused =_=) The gas in a constant-volume gas thermometer has a pressure of 89.0 kPa at 109°C. (a) What is the pressure of the gas at 50.0°C? (b) At what temperature does the gas have a pressure of 115 kPa? A jar of tea is placed in sunlight until it reaches an equilibrium temperature of 39°C. In an attempt to cool the liquid, which has a mass of 195 g, 112 g of ice at 0.0°C is added. At the time at which the temperature of the tea is 15°C, determine the mass of the remaining ice in the jar. Assume the specific heat capacity of the tea to be that of pure liquid water. A 330 g aluminum cup holds and is in thermal equilibrium with 810 g of water at 83°C. The combination of cup and water is cooled uniformly so that the temperature decreases by 1.5°C per minute. At what rate is energy being removed by heat? A student drops two metallic objects into a 120 g steel container holding 150 g of water at 45°C. One object is a 253 g cube of copper that is initially at 85°C, and the other is a chunk of aluminum that is initially at 10°C. To the surprise of the student, the water reaches a final temperature of 45°C, its initial temperature. What is the mass of the aluminum chunk? A hot-water heater is operated by solar power. If the solar collector has an area of 6.0 m2 and the power delivered by sunlight is 550 W/m2, how long will it take to increase the temperature of 1 m3 of water from 23°C to 61°C? A plastic-foam container used as a picnic cooler contains a block of ice at 0.0°C. If 255 g of ice melts in 0.8 h, how much energy passes per second through the wall of the container? A 81 kg cross-country skier moves across snow. The coefficient of kinetic friction between the skis and the snow is 0.20. Assume that all the snow beneath the skis is at 0°C. If all of the energy is absorbed by the snow, how far would the skier have to travel in order to melt 1.3 kg of snow? When a driver brakes an automobile, friction between the brake disks and the brake pads converts part of the car's translational kinetic energy to internal energy. If a 1640 kg automobile traveling at 39 m/s comes to a halt after its brakes are applied, how much can the temperature rise in each of the four 3.5 kg steel brake disks? Assume the disks are made of iron (cp = 448 J/kg·°C) and that all of the kinetic energy is distributed in equal parts to the internal energy of the brakes. A 33.7 g ring that appears to be silver is heated to a temperature of 84°C, and then placed in a calorimeter containing 5.00 multiplied by 10-2 kg of water at 24.0°C. The calorimeter is not perfectly insulated, however, so that 0.14 kJ of energy is transferred by heat to the surroundings by the time a temperature of 25.0°C is reached. From the information provided, can you determine the specific heat capacity of the ring? Is the ring truly made of silver? (Refer to Table 10-4.) thanksss! use the formula PV=nRT

Temperature ( Please show work and formulas used)? 1.In a constant-volume gas thermometer, the pressure at 16.0°C is 0.900 atm. (a) What is the pressure at 42.0°C? atm (b) What is the temperature if the pressure is 0.500 atm? °C 2. The temperature difference between the inside and the outside of an automobile engine is 464°C. (a) Express this temperature difference on the Fahrenheit scale. F° (b) Express this temperature difference on the Kelvin scale. K 3. A copper telephone wire has essentially no sag between poles 36.0 m apart on a winter day when the temperature is -20.0°C. How much longer is the wire on a summer day when TC = 32.0°C? cm Please show worK and formulas used Too much homework

I don't understand this question at all. Please, break it down as simple as you can? Add formulas or equation.? Ethylene glycol is the main component in automobile antifreeze. To monitor the temperature of an auto cooling system, you intend to use a meter that reads from 0 to 100. You devise a new temperature scale based on the approximate melting and boiling points of a typical antifreeze solution (-45°C and 115°C). You wish these points to correspond to 0° and 100°A, respectively. At what temperature would your thermometer and a Celcius thermometer give the same numerical reading? The explaination of this is not that easy to do, I hope this helps..
The question is asking you to design your own temp scale from 1 - 100 to represent ethylene glycol from it's freezing to boiling point.
nb (the temp scale deg celcius was based on water, 0 deg Celcius - freezing point of water. 100 deg celcius = boiling point water)
You want A to go from 0 - 100 A
So you need 0 deg A to be the freezing point of ethylene glycol (-45 deg C)
You need 100 deg A to be the boiling point of ethylene glycol (115 deg C)
The difference betwee -45 deg C and 115 deg C = 160 deg C
So you need to fit 160 deg into your 0-100 scale
Work out how many deg C are going to fit into every deg A
160 / 100
= 1.6
So every one of your new scale (deg A) will represent 1.6 deg Celcius
1 deg A = 1.6 deg C
You can draw it out if it helps, I have done it in 10 deg A increments
10 deg A = 16 deg C
Deg A is on the top and deg C on the bottom.
eg 60 deg A = 51 deg C (from scale below)
Deg A
0 . . . .10 . . .20 . . .30 . . . 40 . . 50 . . . 60 . . .70 . .. 80 . . 90 . . 100
I- - - - -I- - - - -I- - - - -I- - - - -I- - - - -I- - - - -I- - - - -I - - - -I - - - -I - - -- -I
-45 . .-29 . . -13 . . . 3 . . . 19 . . . 35 . . .51 . . .67. .. .83 . . 99 . .115
Deg C
(from the scale above you can see that Deg A and deg C will be the same somewhere between 70 and 80 deg)
Now we need an equation to convert from A to C
We know that 1 A = 1.6 C
And we know that the deg scale starts at -45
So C = (1.6 x A) -45
And if we rearrange the equation we get
A = (C + 45) / 1.6
Try it with 115 deg C
deg A = (115 deg C + 45) / 1.6
= 100 deg A
which is exactly what we wanted 100 deg A to = 115 deg C
when A = 0
C = (1.6 x A) -45
= (1.6 x 0 deg A) -45
= -45 deg C
So at 0 deg A we have -45 deg Cel, also what we wanted, so looks like the equations are good
Now, when deg A and deg C are the same on each scale you can say that
deg A = deg C
which means
A = C = (1.6 x A) -45 = (C + 45) / 1.6
We can solve this for A or C
So A = (1.6 x A) -45
A = 1.6A - 45
therefore 1.6 A - A = 45
therefore 0.6 A = 45
therefore A = 45 / 0.6
= 75 deg A
So A will equal C at 75 deg on the scale.
Lets check it
75 deg C in deg A =
deg A = (C + 45) / 1.6
deg A = (75 deg C + 45) / 1.6
= 75 deg A
and
75 deg A in deg C
deg C = (1.6 x deg A) -45
deg C = (1.6 x 75 deg A) -45
= 75 deg C

desperate please? Out of these inventions, what do you think would be the order of the 10 greatest inventions (in order of importance)? Explain why you chose each one. The inventions are: Computer Automobile Birthday Cake Microwave Motion Picture Alphabet Gunpowder Chocolate Wheel Thermometer Baseball Watches Plastic Brick Lipstick Printing Press Gel Pens Oven Airplane Clock Map Paper Pencil Telephone Refrigerator Compass Money Space Shuttle Compass - exploration, navigation, conquering new lands
Map - exploration, navigation, conquering new lands
Clock - exploration, navigation, conquering new lands
Wheel - moving goods, supply lines, conquest
Gunpowder - protection and conquest
Alphabet - communication
Pencil - communication
Paper - communication
Printing Press - communication
Money - commerce
The reason I have selected the simplest as the greatest inventions is because they were invented with no prior experience or knowledge. They did not resemble anything that had ever existed and were the direct result of somebody thinking deeply about how to solve a problem with no science, math, or other ideas that preceeded it.
This assumes going back to the beginning and you are starting from scratch, with everybody living in one place and now they need to spread out and conquer the world.
You need basic things. Airplanes and ovens and microwaves and computers will come later... but the most important inventions are those that will provide you with the ability to spread out, communicate, engage in commerce, and protect yourself. Each of these ten items I have selected are really important for that to happen. I would have added knive to the list of choices as that was the earliest form of protection and hunting for food. With these ten items you can live, grow, reproduce, and conquer the earth.

Automobile Thermometer is from category: Flashlights.